Can reflection result in plane polarised light if the light is incident on the interface from the side with higher refractive index?

(YES) Here,the incident ray is in the denser medium (medium-$2$) and the refracted ray is in the rarer medium (medium-$1$). Hence,according to Brewster's law,
$\tan \theta_{P} = \frac{n_{1}}{n_{2}} \quad \ldots (1)$
(Where $\theta_{P} =$ polarisation angle or Brewster angle)
Here,if the critical angle of the denser medium with respect to the rarer medium is $C$,then according to Snell's law,$n_{2} \sin C = n_{1} \sin 90^{\circ}$
$\therefore \sin C = \frac{n_{1}}{n_{2}} \quad \ldots (2)$
From equations $(1)$ and $(2)$,$\tan \theta_{P} = \sin C$
$\therefore \frac{\sin \theta_{P}}{\cos \theta_{P}} = \sin C$
$\therefore \sin \theta_{P} = (\cos \theta_{P}) \sin C$
But here $0 < \cos \theta_{P} < 1$
$\Rightarrow \sin \theta_{P} < \sin C$
$\therefore \theta_{P} < C$
For a ray of light incident on the surface of the rarer medium at the polarisation angle,satisfying the above condition,the reflected light will be completely plane polarised.